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6y^2+33y+36=0
a = 6; b = 33; c = +36;
Δ = b2-4ac
Δ = 332-4·6·36
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-15}{2*6}=\frac{-48}{12} =-4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+15}{2*6}=\frac{-18}{12} =-1+1/2 $
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